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LOGARITHMIC INEQUALITY
Q1–10 of 40
1

If log₂(x−1)>4, then

Correct Answer: B. x>17
Explanation:


  • Domain: $x - 1 > 0 \implies x > 1$.

  • Inequality (Base $2 > 1$): $x - 1 > 2^4 = 16 \implies x > 17$.

  • Correct Answer: B. $x > 17$

  • 2

    The solution of log₅(2x+1) ≤ 2 is

    Correct Answer: B. −1/2<x≤12
    Explanation:


  • Domain: $2x + 1 > 0 \implies x > -1/2$.

  • Inequality (Base $5 > 1$): $2x + 1 \le 5^2 = 25 \implies 2x \le 24 \implies x \le 12$.

  • Combined: $-1/2 < x \le 12$.

  • Correct Answer: B. $-1/2 < x \le 12$

  • 3

    If log1/3(x+2) ≥ −2, then

    Correct Answer: B. −2<x≤7
    Explanation:


  • Domain: $x + 2 > 0 \implies x > -2$.

  • Inequality (Base $1/3 < 1$, flip inequality):

    $$x + 2 \le (1/3)^{-2} = 9 \implies x \le 7$$

  • Combined: $-2 < x \le 7$.

  • Correct Answer: B. $-2 < x \le 7$

  • 4

    If log₇(x+5) ≥ log₇12, then

    Correct Answer: A. x≥7
    Explanation:


  • Domain: $x + 5 > 0 \implies x > -5$.

  • Inequality (Base $7 > 1$): $x + 5 \ge 12 \implies x \ge 7$.

  • Correct Answer: A. $x \ge 7$

  • 5

    Solve: log₂(x+1) < log₂(3x−5)

    Correct Answer: C. x>3
    Explanation:


  • Domain: $x + 1 > 0 \implies x > -1$, and $3x - 5 > 0 \implies x > 5/3$.

  • Inequality (Base $2 > 1$): $x + 1 < 3x - 5 \implies 2x > 6 \implies x > 3$.

  • Combined: $x > 3$.

  • Correct Answer: C. $x > 3$

  • 6

    The solution of log₉(x²) > 1 is

    Correct Answer: B. x<−3 or x>3
    Explanation:


  • Domain: $x^2 > 0 \implies x \ne 0$.

  • Inequality (Base $9 > 1$): $x^2 > 9^1 = 9 \implies \vert{}x\vert{} > 3 \implies x < -3 \text{ or } x > 3$.

  • Correct Answer: B. $x < -3 \text{ or } x > 3$

  • 7

    If log₃(x+2) < log₃27 then


    Correct Answer: D. −2<x<25
    Explanation:


  • Domain: $x + 2 > 0 \implies x > -2$.

  • Inequality (Base $3 > 1$): $x + 2 < 27 \implies x < 25$.

  • Combined: $-2 < x < 25$.

  • Correct Answer: D. $-2 < x < 25$

  • 8

    The solution of log₂(x²−5) > 2 is

    Correct Answer: A. x<−3 or x>3
    Explanation:


  • Domain: $x^2 - 5 > 0 \implies x < -\sqrt{5} \text{ or } x > \sqrt{5}$.

  • Inequality (Base $2 > 1$): $x^2 - 5 > 2^2 = 4 \implies x^2 > 9 \implies x < -3 \text{ or } x > 3$.

  • Correct Answer: A. $x < -3 \text{ or } x > 3$

  • 9

    Solve : log₅(x−1) ≥ log₅(2x−8)

    Correct Answer: C. 4<x≤7
    Explanation:


  • Domain: $x - 1 > 0 \implies x > 1$, and $2x - 8 > 0 \implies x > 4$.

  • Inequality (Base $5 > 1$): $x - 1 \ge 2x - 8 \implies x \le 7$.

  • Combined: $4 < x \le 7$ (matching Option C; option B listed in key corresponds to $x>7$ variant).

  • Correct Answer: C. $4 < x \le 7$

  • 10

    If log₂(x+3) > log₂(7−x) then

    Correct Answer: A. 2<x<7
    Explanation:


  • Domain: $x + 3 > 0 \implies x > -3$, and $7 - x > 0 \implies x < 7$.

  • Inequality (Base $2 > 1$): $x + 3 > 7 - x \implies 2x > 4 \implies x > 2$.

  • Combined: $2 < x < 7$.

  • Correct Answer: A. $2 < x < 7$

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